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x^2+x-2450=0
a = 1; b = 1; c = -2450;
Δ = b2-4ac
Δ = 12-4·1·(-2450)
Δ = 9801
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{9801}=99$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1)-99}{2*1}=\frac{-100}{2} =-50 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1)+99}{2*1}=\frac{98}{2} =49 $
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